DatePart Function
The DatePart function returns a specified part of a date.
DatePart (interval As String, date As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Long
Врати вредност:
The extracted part for the given date.
 interval - A string expression from the following table, specifying the date interval.
  
    | interval (string value) | Explanation | 
  
    | yyyy | Year | 
  
    | q | Quarter | 
  
    | m | Month | 
  
    | y | Day of year | 
  
    | w | Weekday | 
  
    | ww | Week of year | 
  
    | d | Day | 
  
    | h | Hour | 
  
    | n | Minute | 
  
    | s | Second | 
 
 date - The date from which the result is calculated.
Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:
    - 
        #yyyy-mm-dd# 
- 
        #mm/dd/yyyy# 
 
 firstdayofweek: An optional parameter that specifies the starting day of a week.
  
    | firstdayofweek value | Explanation | 
  
    | 0 | Use system default value | 
  
    | 1 | Sunday (default) | 
  
    | 2 | Monday | 
  
    | 3 | Tuesday | 
  
    | 4 | Wednesday | 
  
    | 5 | Thursday | 
  
    | 6 | Friday | 
  
    | 7 | Saturday | 
 firstweekofyear: An optional parameter that specifies the starting week of a year.
  
    | firstweekofyear value | Explanation | 
  
    | 0 | Use system default value | 
  
    | 1 | Week 1 is the week with January, 1st (default) | 
  
    | 2 | Week 1 is the first week containing four or more days of that year | 
  
    | 3 | Week 1 is the first week containing only days of the new year | 
 
Sub example_datepart
    MsgBox DatePart("ww", #01/02/2005#) ' displays 2 because weeks start on Sunday
    MsgBox DatePart("ww", #12/31/2005#) ' displays 53
    MsgBox DatePart(date:=#2005-12-30#, interval:="q") ' displays 4
End Sub